String length/ brace height

[DC]

I just made a string for a new bow. It's a little short. I was curious how much too short but I didn't know of any relationship between string length and brace height. I braced my regular shooter and measured the brace height. It was 5". Then I wrapped the string once around a 1/8" wire which shortened the string by about 3/8". The brace height went up to 5 3/4". So this is a 2:1 relationship. At least for this bow. Do you know if this relationship holds true for most bows or does it vary quite a bit?

[BowEd]

I usually make a string as long as what my tillering string was.

[Badger]

  A string 3" short will usually give you about a 6" brace so that sounds about right. I just twist mine up or down to where I want them. You don't have to get them right on the money.

[DC]

  A string 3" short will usually give you about a 6" brace so that sounds about right. I just twist mine up or down to where I want them. You don't have to get them right on the money.

To answer the question on my other thread, how much can you change the length by twisting it?

[Badger]

  A string 3" short will usually give you about a 6" brace so that sounds about right. I just twist mine up or down to where I want them. You don't have to get them right on the money.

To answer the question on my other thread, how much can you change the length by twisting it?

  You can twist it up 3 or more inches if you like, best to stay within an inch or so but no difference in the way the bow shoots if you twist it up 3". I do it all the time.

[BowEd]

Dc....Yes what Steve said there.The same string can be used on different bows.I do that here too.

[Ryan Jacob]

Hope this won’t be too confusing...
I’ve found that this is the formula:

Brace Height= ((ntn length - string length) X 2) - (string length X %stretch)

In real words, the brace height is the difference of ntn length and string length, and accomodate for stretch... now that I think about it, it’s probably still confusing.

[Del the cat]

Hope this won’t be too confusing...
I’ve found that this is the formula:

Brace Height= ((ntn length - string length) X 2) - (string length X %stretch)

In real words, the brace height is the difference of ntn length and string length, and accomodate for stretch... now that I think about it, it’s probably still confusing.

That's like a damn maths question.
Rearrange the following equation to give sting length! sheesh!
I'll have a go.
let brace height=b, ntn length = n, string length = l, % stretch = s

b=(n-l)x2 - lxs
therefore b=2n-2l-ls
therefore b=2n-(2-s)l
therefore (2-s)l=2n-b
and finally, therefore
l=(2n-b)/(2-s)     ta da!

Errrr so... hmmm if I can remeber what the letters all stood for 

string length=2x ntn length-brace height divided by 2x %stretch

Not sure if it's any help or even correct, but it exercised the old grey matter 
Del
PS Ryan, do I get paid for doing your homework

[Ryan Jacob]

 It is close enough from my experience, also makes sense (math wise), now do you want the payment per hour or per problem  ... Actually gonna stop now pretty sure a moderator or admins gonna get mad if we keep discussing payments

[Del the cat]

Will work for kitty treats 
Del

[Hawkdancer]

 , what's the old standby rule of thumb, 3" short for straight bows, 4" short for recurves, of ntn,  then adjust to suit your bow? (no string maker emoji)!  Not being real sharp on string/bow making, I try to match the old string and go about an inch shorter to account for stretch.  Also get brace height a bit more than fletch length for clearance.  No formula, I flunked math!
Hawkdancer

[Ryan Jacob]

Del
I think you actually screwed up on the first bit,

That's like a damn maths question.
Rearrange the following equation to give sting length! sheesh!
I'll have a go.
let brace height=b, ntn length = n, string length = l, % stretch = s

b=(n-l)x2 - lxs
therefore b=2n-2l-ls
therefore b=2n-(2-s)l
therefore (2-s)l=2n-b
and finally, therefore
l=(2n-b)/(2-s)     ta da!

Errrr so... hmmm if I can remeber what the letters all stood for 

string length=2x ntn length-brace height divided by 2x %stretch

Not sure if it's any help or even correct, but it exercised the old grey matter 
Del
PS Ryan, do I get paid for doing your homework

The formula should actually look like this (using your symbols) :

b= ((n-l)x2) - (lxs)
b= ((n-l)x2) - (ls)

That’s for brace, you cant multiply 2 to (n-l) until you actually plug in the numbers (at least when you actually will put numbers instead of letters)

for string length...

l= ((n x (b/2)) + (lxs)

Good Luck with these, , I’m not doing anymore math, my heads starting to hurt

[Del the cat]

@ Ryan
"you cant multiply 2 to (n-l) until you actually plug in the numbers (at least when you actually will put numbers instead of letters)"

Errr, Sorry but yes you can, it's basic algebra it works regardless of plugging in letters, numbers or scraps of old deer skin.
2(a-b) expands to 2a-2b

Not the place for a maths debate, mind there are some maths debaters on some forums
Del
PS. If You can find any numbers for a and b that won't work I'll pay £50 £100 to the charity of your choice!

[Ryan Jacob]

Got it, what did I expect I’m in high school ... maybe I screwed up the first equation... wait, sorry, I read your math wrong